## Potato sucrose gulaman

1 Answer to 8. Find the vector equation of the line in which the 2 planes 2x - 5y + 3z = 12 and 3x + 4y - 3z = 6 meet.

Hence, we will need to find a normal vector. We can do this with the use of the cross product, however, we will need to find two parallel vectors first. We can easily do this with utilization of the points given. Let's use the vector formed from the cross product of $\vec{PQ} = (-11, 0, 1)$ and $\vec{PR} = (1, -2, 2)$ (3)

Solution: These two lines intersect if there exist values of tand s such that r1(t) = r2(s). Equating each of the three components, we get three equations, which we try to solve for t and s. If a simultaneous solution exists, the lines intersect; if not, they don’t. t= 3− 4s 1−2t= 2+ 3s 2+3t= 1− 2s.

I The line of intersection of two planes. I Parallel planes and angle between planes. I Distance from a point to a plane. Review: Lines on a plane Equation of a line The equation of a line with slope m and vertical intercept b is given by y = mx + b. 1 x y b 1 m Vector equation of a line The equation of the line by the point P = (0,b) parallel to the vector v = h1,mi is given by r(t) = r 0 + t v, where r

Dec 21, 2020 · To write an equation for a line, we must know two points on the line, or we must know the direction of the line and at least one point through which the line passes. In two dimensions, we use the … 12.5: Equations of Lines and Planes in Space - Mathematics LibreTexts

1 Answer to 8. Find the vector equation of the line in which the 2 planes 2x - 5y + 3z = 12 and 3x + 4y - 3z = 6 meet.